(4x^-5/7y^-8)^-3

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Solution for (4x^-5/7y^-8)^-3 equation: 


D( x )

x = 0

((4*x^-5)/7)*y^-8 = 0

x = 0

x = 0

((4*x^-5)/7)*y^-8 = 0

((4*x^-5)/7)*y^-8 = 0

4/7*x^-5*y^-8 = 0 // : 4/7*y^-8

x^-5 = 0

x należy do O

x in (-oo:0) U (0:+oo)

(((4*x^-5)/7)*y^-8)^-3 = 0

343/64*x^15*y^24 = 0 // : 343/64*y^24

x^15 = 0

x = 0

x in { 0} 

x belongs to the empty set

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